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Solution - Absolute value equations

Exact form:

v = - 1

v=-1

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 4 v + 2 | = | 4 v + 6 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 4 v + 2 \| = \| 4 v + 6 \|$
$x = + y$	$(4 v + 2) = (4 v + 6)$
$x = - y$	$(4 v + 2) = - (4 v + 6)$
$+ x = y$	$(4 v + 2) = (4 v + 6)$
$- x = y$	$- (4 v + 2) = (4 v + 6)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 4 v + 2 \| = \| 4 v + 6 \|$
$x = + y$ , $+ x = y$	$(4 v + 2) = (4 v + 6)$
$x = - y$ , $- x = y$	$(4 v + 2) = - (4 v + 6)$

2. Solve the two equations for v

5 additional steps

$(4 v + 2) = (4 v + 6)$

Subtract from both sides:

$(4 v + 2) - 4 v = (4 v + 6) - 4 v$

Group like terms:

$(4 v - 4 v) + 2 = (4 v + 6) - 4 v$

Simplify the arithmetic:

$2 = (4 v + 6) - 4 v$

Group like terms:

$2 = (4 v - 4 v) + 6$

Simplify the arithmetic:

$2 = 6$

The statement is false:

$2 = 6$

The equation is false so it has no solution.

11 additional steps

$(4 v + 2) = - (4 v + 6)$

Expand the parentheses:

$(4 v + 2) = - 4 v - 6$

Add to both sides:

$(4 v + 2) + 4 v = (- 4 v - 6) + 4 v$

Group like terms:

$(4 v + 4 v) + 2 = (- 4 v - 6) + 4 v$

Simplify the arithmetic:

$8 v + 2 = (- 4 v - 6) + 4 v$

Group like terms:

$8 v + 2 = (- 4 v + 4 v) - 6$

Simplify the arithmetic:

$8 v + 2 = - 6$

Subtract from both sides:

$(8 v + 2) - 2 = - 6 - 2$

Simplify the arithmetic:

$8 v = - 6 - 2$

Simplify the arithmetic:

$8 v = - 8$

Divide both sides by :

$\frac{(8 v)}{8} = \frac{- 8}{8}$

Simplify the fraction:

$v = \frac{- 8}{8}$

Simplify the fraction:

$v = - 1$

3. Graph

Each line represents the function of one side of the equation:
$y = | 4 v + 2 |$
$y = | 4 v + 6 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for v

3. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for v

3. Graph

Why learn this

Terms and topics

Related links

Latest Related Drills Solved