Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: q=-12,56
q=-\frac{1}{2} , \frac{5}{6}
Decimal form: q=0.5,0.833
q=-0.5 , 0.833

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4q2|=|2q3|
without the absolute value bars:

|x|=|y||4q2|=|2q3|
x=+y(4q2)=(2q3)
x=y(4q2)=(2q3)
+x=y(4q2)=(2q3)
x=y(4q2)=(2q3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4q2|=|2q3|
x=+y , +x=y(4q2)=(2q3)
x=y , x=y(4q2)=(2q3)

2. Solve the two equations for q

9 additional steps

(4q-2)=(2q-3)

Subtract from both sides:

(4q-2)-2q=(2q-3)-2q

Group like terms:

(4q-2q)-2=(2q-3)-2q

Simplify the arithmetic:

2q-2=(2q-3)-2q

Group like terms:

2q-2=(2q-2q)-3

Simplify the arithmetic:

2q2=3

Add to both sides:

(2q-2)+2=-3+2

Simplify the arithmetic:

2q=3+2

Simplify the arithmetic:

2q=1

Divide both sides by :

(2q)2=-12

Simplify the fraction:

q=-12

10 additional steps

(4q-2)=-(2q-3)

Expand the parentheses:

(4q-2)=-2q+3

Add to both sides:

(4q-2)+2q=(-2q+3)+2q

Group like terms:

(4q+2q)-2=(-2q+3)+2q

Simplify the arithmetic:

6q-2=(-2q+3)+2q

Group like terms:

6q-2=(-2q+2q)+3

Simplify the arithmetic:

6q2=3

Add to both sides:

(6q-2)+2=3+2

Simplify the arithmetic:

6q=3+2

Simplify the arithmetic:

6q=5

Divide both sides by :

(6q)6=56

Simplify the fraction:

q=56

3. List the solutions

q=-12,56
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4q2|
y=|2q3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.