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Solution - Absolute value equations

Exact form: q=-92,-76
q=-\frac{9}{2} , -\frac{7}{6}
Mixed number form: q=-412,-116
q=-4\frac{1}{2} , -1\frac{1}{6}
Decimal form: q=4.5,1.167
q=-4.5 , -1.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4q+8|=|2q1|
without the absolute value bars:

|x|=|y||4q+8|=|2q1|
x=+y(4q+8)=(2q1)
x=y(4q+8)=(2q1)
+x=y(4q+8)=(2q1)
x=y(4q+8)=(2q1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4q+8|=|2q1|
x=+y , +x=y(4q+8)=(2q1)
x=y , x=y(4q+8)=(2q1)

2. Solve the two equations for q

9 additional steps

(4q+8)=(2q-1)

Subtract from both sides:

(4q+8)-2q=(2q-1)-2q

Group like terms:

(4q-2q)+8=(2q-1)-2q

Simplify the arithmetic:

2q+8=(2q-1)-2q

Group like terms:

2q+8=(2q-2q)-1

Simplify the arithmetic:

2q+8=1

Subtract from both sides:

(2q+8)-8=-1-8

Simplify the arithmetic:

2q=18

Simplify the arithmetic:

2q=9

Divide both sides by :

(2q)2=-92

Simplify the fraction:

q=-92

10 additional steps

(4q+8)=-(2q-1)

Expand the parentheses:

(4q+8)=-2q+1

Add to both sides:

(4q+8)+2q=(-2q+1)+2q

Group like terms:

(4q+2q)+8=(-2q+1)+2q

Simplify the arithmetic:

6q+8=(-2q+1)+2q

Group like terms:

6q+8=(-2q+2q)+1

Simplify the arithmetic:

6q+8=1

Subtract from both sides:

(6q+8)-8=1-8

Simplify the arithmetic:

6q=18

Simplify the arithmetic:

6q=7

Divide both sides by :

(6q)6=-76

Simplify the fraction:

q=-76

3. List the solutions

q=-92,-76
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4q+8|
y=|2q1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.