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Solution - Absolute value equations

Exact form: p=32,12
p=\frac{3}{2} , \frac{1}{2}
Mixed number form: p=112,12
p=1\frac{1}{2} , \frac{1}{2}
Decimal form: p=1.5,0.5
p=1.5 , 0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4p3|=|2p|
without the absolute value bars:

|x|=|y||4p3|=|2p|
x=+y(4p3)=(2p)
x=y(4p3)=(2p)
+x=y(4p3)=(2p)
x=y(4p3)=(2p)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4p3|=|2p|
x=+y , +x=y(4p3)=(2p)
x=y , x=y(4p3)=(2p)

2. Solve the two equations for p

8 additional steps

(4p-3)=2p

Subtract from both sides:

(4p-3)-2p=(2p)-2p

Group like terms:

(4p-2p)-3=(2p)-2p

Simplify the arithmetic:

2p-3=(2p)-2p

Simplify the arithmetic:

2p3=0

Add to both sides:

(2p-3)+3=0+3

Simplify the arithmetic:

2p=0+3

Simplify the arithmetic:

2p=3

Divide both sides by :

(2p)2=32

Simplify the fraction:

p=32

9 additional steps

(4p-3)=-2p

Add to both sides:

(4p-3)+3=(-2p)+3

Simplify the arithmetic:

4p=(-2p)+3

Add to both sides:

(4p)+2p=((-2p)+3)+2p

Simplify the arithmetic:

6p=((-2p)+3)+2p

Group like terms:

6p=(-2p+2p)+3

Simplify the arithmetic:

6p=3

Divide both sides by :

(6p)6=36

Simplify the fraction:

p=36

Find the greatest common factor of the numerator and denominator:

p=(1·3)(2·3)

Factor out and cancel the greatest common factor:

p=12

3. List the solutions

p=32,12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4p3|
y=|2p|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.