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Solution - Absolute value equations

Exact form: n=5,3
n=-5 , -3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4n+15|=|n|
without the absolute value bars:

|x|=|y||4n+15|=|n|
x=+y(4n+15)=(n)
x=y(4n+15)=(n)
+x=y(4n+15)=(n)
x=y(4n+15)=(n)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4n+15|=|n|
x=+y , +x=y(4n+15)=(n)
x=y , x=y(4n+15)=(n)

2. Solve the two equations for n

10 additional steps

(4n+15)=n

Subtract from both sides:

(4n+15)-n=n-n

Group like terms:

(4n-n)+15=n-n

Simplify the arithmetic:

3n+15=nn

Simplify the arithmetic:

3n+15=0

Subtract from both sides:

(3n+15)-15=0-15

Simplify the arithmetic:

3n=015

Simplify the arithmetic:

3n=15

Divide both sides by :

(3n)3=-153

Simplify the fraction:

n=-153

Find the greatest common factor of the numerator and denominator:

n=(-5·3)(1·3)

Factor out and cancel the greatest common factor:

n=5

10 additional steps

(4n+15)=-n

Add to both sides:

(4n+15)+n=-n+n

Group like terms:

(4n+n)+15=-n+n

Simplify the arithmetic:

5n+15=n+n

Simplify the arithmetic:

5n+15=0

Subtract from both sides:

(5n+15)-15=0-15

Simplify the arithmetic:

5n=015

Simplify the arithmetic:

5n=15

Divide both sides by :

(5n)5=-155

Simplify the fraction:

n=-155

Find the greatest common factor of the numerator and denominator:

n=(-3·5)(1·5)

Factor out and cancel the greatest common factor:

n=3

3. List the solutions

n=5,3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4n+15|
y=|n|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.