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Solution - Absolute value equations

Exact form: k=-2,27
k=-2 , \frac{2}{7}
Decimal form: k=2,0.286
k=-2 , 0.286

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4k|=|3k2|
without the absolute value bars:

|x|=|y||4k|=|3k2|
x=+y(4k)=(3k2)
x=y(4k)=(3k2)
+x=y(4k)=(3k2)
x=y(4k)=(3k2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4k|=|3k2|
x=+y , +x=y(4k)=(3k2)
x=y , x=y(4k)=(3k2)

2. Solve the two equations for k

3 additional steps

4k=(3k-2)

Subtract from both sides:

(4k)-3k=(3k-2)-3k

Simplify the arithmetic:

k=(3k-2)-3k

Group like terms:

k=(3k-3k)-2

Simplify the arithmetic:

k=2

6 additional steps

4k=-(3k-2)

Expand the parentheses:

4k=3k+2

Add to both sides:

(4k)+3k=(-3k+2)+3k

Simplify the arithmetic:

7k=(-3k+2)+3k

Group like terms:

7k=(-3k+3k)+2

Simplify the arithmetic:

7k=2

Divide both sides by :

(7k)7=27

Simplify the fraction:

k=27

3. List the solutions

k=-2,27
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4k|
y=|3k2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.