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Solution - Absolute value equations

Exact form: k=-7,-37
k=-7 , -\frac{3}{7}
Decimal form: k=7,0.429
k=-7 , -0.429

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4k+5|=|3k2|
without the absolute value bars:

|x|=|y||4k+5|=|3k2|
x=+y(4k+5)=(3k2)
x=y(4k+5)=(3k2)
+x=y(4k+5)=(3k2)
x=y(4k+5)=(3k2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4k+5|=|3k2|
x=+y , +x=y(4k+5)=(3k2)
x=y , x=y(4k+5)=(3k2)

2. Solve the two equations for k

7 additional steps

(4k+5)=(3k-2)

Subtract from both sides:

(4k+5)-3k=(3k-2)-3k

Group like terms:

(4k-3k)+5=(3k-2)-3k

Simplify the arithmetic:

k+5=(3k-2)-3k

Group like terms:

k+5=(3k-3k)-2

Simplify the arithmetic:

k+5=2

Subtract from both sides:

(k+5)-5=-2-5

Simplify the arithmetic:

k=25

Simplify the arithmetic:

k=7

10 additional steps

(4k+5)=-(3k-2)

Expand the parentheses:

(4k+5)=-3k+2

Add to both sides:

(4k+5)+3k=(-3k+2)+3k

Group like terms:

(4k+3k)+5=(-3k+2)+3k

Simplify the arithmetic:

7k+5=(-3k+2)+3k

Group like terms:

7k+5=(-3k+3k)+2

Simplify the arithmetic:

7k+5=2

Subtract from both sides:

(7k+5)-5=2-5

Simplify the arithmetic:

7k=25

Simplify the arithmetic:

7k=3

Divide both sides by :

(7k)7=-37

Simplify the fraction:

k=-37

3. List the solutions

k=-7,-37
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4k+5|
y=|3k2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.