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Solution - Absolute value equations

Exact form: c=-1,-115
c=-1 , -\frac{11}{5}
Mixed number form: c=-1,-215
c=-1 , -2\frac{1}{5}
Decimal form: c=1,2.2
c=-1 , -2.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4c+7|=|c+4|
without the absolute value bars:

|x|=|y||4c+7|=|c+4|
x=+y(4c+7)=(c+4)
x=y(4c+7)=(c+4)
+x=y(4c+7)=(c+4)
x=y(4c+7)=(c+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4c+7|=|c+4|
x=+y , +x=y(4c+7)=(c+4)
x=y , x=y(4c+7)=(c+4)

2. Solve the two equations for c

10 additional steps

(4c+7)=(c+4)

Subtract from both sides:

(4c+7)-c=(c+4)-c

Group like terms:

(4c-c)+7=(c+4)-c

Simplify the arithmetic:

3c+7=(c+4)-c

Group like terms:

3c+7=(c-c)+4

Simplify the arithmetic:

3c+7=4

Subtract from both sides:

(3c+7)-7=4-7

Simplify the arithmetic:

3c=47

Simplify the arithmetic:

3c=3

Divide both sides by :

(3c)3=-33

Simplify the fraction:

c=-33

Simplify the fraction:

c=1

10 additional steps

(4c+7)=-(c+4)

Expand the parentheses:

(4c+7)=-c-4

Add to both sides:

(4c+7)+c=(-c-4)+c

Group like terms:

(4c+c)+7=(-c-4)+c

Simplify the arithmetic:

5c+7=(-c-4)+c

Group like terms:

5c+7=(-c+c)-4

Simplify the arithmetic:

5c+7=4

Subtract from both sides:

(5c+7)-7=-4-7

Simplify the arithmetic:

5c=47

Simplify the arithmetic:

5c=11

Divide both sides by :

(5c)5=-115

Simplify the fraction:

c=-115

3. List the solutions

c=-1,-115
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4c+7|
y=|c+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.