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Solution - Absolute value equations

Exact form: a=-73,-1
a=-\frac{7}{3} , -1
Mixed number form: a=-213,-1
a=-2\frac{1}{3} , -1
Decimal form: a=2.333,1
a=-2.333 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4a+8|=|2a6|
without the absolute value bars:

|x|=|y||4a+8|=|2a6|
x=+y(4a+8)=(2a6)
x=y(4a+8)=(2a6)
+x=y(4a+8)=(2a6)
x=y(4a+8)=(2a6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4a+8|=|2a6|
x=+y , +x=y(4a+8)=(2a6)
x=y , x=y(4a+8)=(2a6)

2. Solve the two equations for a

11 additional steps

(4a+8)=(-2a-6)

Add to both sides:

(4a+8)+2a=(-2a-6)+2a

Group like terms:

(4a+2a)+8=(-2a-6)+2a

Simplify the arithmetic:

6a+8=(-2a-6)+2a

Group like terms:

6a+8=(-2a+2a)-6

Simplify the arithmetic:

6a+8=6

Subtract from both sides:

(6a+8)-8=-6-8

Simplify the arithmetic:

6a=68

Simplify the arithmetic:

6a=14

Divide both sides by :

(6a)6=-146

Simplify the fraction:

a=-146

Find the greatest common factor of the numerator and denominator:

a=(-7·2)(3·2)

Factor out and cancel the greatest common factor:

a=-73

11 additional steps

(4a+8)=-(-2a-6)

Expand the parentheses:

(4a+8)=2a+6

Subtract from both sides:

(4a+8)-2a=(2a+6)-2a

Group like terms:

(4a-2a)+8=(2a+6)-2a

Simplify the arithmetic:

2a+8=(2a+6)-2a

Group like terms:

2a+8=(2a-2a)+6

Simplify the arithmetic:

2a+8=6

Subtract from both sides:

(2a+8)-8=6-8

Simplify the arithmetic:

2a=68

Simplify the arithmetic:

2a=2

Divide both sides by :

(2a)2=-22

Simplify the fraction:

a=-22

Simplify the fraction:

a=1

3. List the solutions

a=-73,-1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4a+8|
y=|2a6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.