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Solution - Absolute value equations

Exact form: x=1,19
x=1 , \frac{1}{9}
Decimal form: x=1,0.111
x=1 , 0.111

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|40x|=|50x10|
without the absolute value bars:

|x|=|y||40x|=|50x10|
x=+y(40x)=(50x10)
x=y(40x)=(50x10)
+x=y(40x)=(50x10)
x=y(40x)=(50x10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||40x|=|50x10|
x=+y , +x=y(40x)=(50x10)
x=y , x=y(40x)=(50x10)

2. Solve the two equations for x

8 additional steps

40x=(50x-10)

Subtract from both sides:

(40x)-50x=(50x-10)-50x

Simplify the arithmetic:

-10x=(50x-10)-50x

Group like terms:

-10x=(50x-50x)-10

Simplify the arithmetic:

10x=10

Divide both sides by :

(-10x)-10=-10-10

Cancel out the negatives:

10x10=-10-10

Simplify the fraction:

x=-10-10

Cancel out the negatives:

x=1010

Simplify the fraction:

x=1

8 additional steps

40x=-(50x-10)

Expand the parentheses:

40x=50x+10

Add to both sides:

(40x)+50x=(-50x+10)+50x

Simplify the arithmetic:

90x=(-50x+10)+50x

Group like terms:

90x=(-50x+50x)+10

Simplify the arithmetic:

90x=10

Divide both sides by :

(90x)90=1090

Simplify the fraction:

x=1090

Find the greatest common factor of the numerator and denominator:

x=(1·10)(9·10)

Factor out and cancel the greatest common factor:

x=19

3. List the solutions

x=1,19
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|40x|
y=|50x10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.