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Solution - Absolute value equations

Exact form: x=25,-12
x=\frac{2}{5} , -\frac{1}{2}
Decimal form: x=0.4,0.5
x=0.4 , -0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+4|=9|x|
without the absolute value bars:

|x|=|y||x+4|=9|x|
x=+y(x+4)=9(x)
x=y(x+4)=9((x))
+x=y(x+4)=9(x)
x=y(x+4)=9(x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+4|=9|x|
x=+y , +x=y(x+4)=9(x)
x=y , x=y(x+4)=9((x))

2. Solve the two equations for x

12 additional steps

(-x+4)=9x

Subtract from both sides:

(-x+4)-9x=(9x)-9x

Group like terms:

(-x-9x)+4=(9x)-9x

Simplify the arithmetic:

-10x+4=(9x)-9x

Simplify the arithmetic:

10x+4=0

Subtract from both sides:

(-10x+4)-4=0-4

Simplify the arithmetic:

10x=04

Simplify the arithmetic:

10x=4

Divide both sides by :

(-10x)-10=-4-10

Cancel out the negatives:

10x10=-4-10

Simplify the fraction:

x=-4-10

Cancel out the negatives:

x=410

Find the greatest common factor of the numerator and denominator:

x=(2·2)(5·2)

Factor out and cancel the greatest common factor:

x=25

12 additional steps

(-x+4)=9·-x

Group like terms:

(-x+4)=(9·-1)x

Multiply the coefficients:

(-x+4)=-9x

Add to both sides:

(-x+4)+9x=(-9x)+9x

Group like terms:

(-x+9x)+4=(-9x)+9x

Simplify the arithmetic:

8x+4=(-9x)+9x

Simplify the arithmetic:

8x+4=0

Subtract from both sides:

(8x+4)-4=0-4

Simplify the arithmetic:

8x=04

Simplify the arithmetic:

8x=4

Divide both sides by :

(8x)8=-48

Simplify the fraction:

x=-48

Find the greatest common factor of the numerator and denominator:

x=(-1·4)(2·4)

Factor out and cancel the greatest common factor:

x=-12

3. List the solutions

x=25,-12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+4|
y=9|x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.