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Solution - Absolute value equations

Exact form: x=1
x=1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+4|=|3x+2|
without the absolute value bars:

|x|=|y||3x+4|=|3x+2|
x=+y(3x+4)=(3x+2)
x=y(3x+4)=(3x+2)
+x=y(3x+4)=(3x+2)
x=y(3x+4)=(3x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+4|=|3x+2|
x=+y , +x=y(3x+4)=(3x+2)
x=y , x=y(3x+4)=(3x+2)

2. Solve the two equations for x

5 additional steps

(-3x+4)=(-3x+2)

Add to both sides:

(-3x+4)+3x=(-3x+2)+3x

Group like terms:

(-3x+3x)+4=(-3x+2)+3x

Simplify the arithmetic:

4=(-3x+2)+3x

Group like terms:

4=(-3x+3x)+2

Simplify the arithmetic:

4=2

The statement is false:

4=2

The equation is false so it has no solution.

13 additional steps

(-3x+4)=-(-3x+2)

Expand the parentheses:

(-3x+4)=3x-2

Subtract from both sides:

(-3x+4)-3x=(3x-2)-3x

Group like terms:

(-3x-3x)+4=(3x-2)-3x

Simplify the arithmetic:

-6x+4=(3x-2)-3x

Group like terms:

-6x+4=(3x-3x)-2

Simplify the arithmetic:

6x+4=2

Subtract from both sides:

(-6x+4)-4=-2-4

Simplify the arithmetic:

6x=24

Simplify the arithmetic:

6x=6

Divide both sides by :

(-6x)-6=-6-6

Cancel out the negatives:

6x6=-6-6

Simplify the fraction:

x=-6-6

Cancel out the negatives:

x=66

Simplify the fraction:

x=1

3. Graph

Each line represents the function of one side of the equation:
y=|3x+4|
y=|3x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.