Enter an equation or problem

Camera input is not recognized!

Solution - Absolute value equations

Exact form:

y = \frac{2}{3}

y=\frac{2}{3}

Decimal form:

y = 0.667

y=0.667

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 3 y | = | 3 y - 4 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 3 y \| = \| 3 y - 4 \|$
$x = + y$	$(3 y) = (3 y - 4)$
$x = - y$	$(3 y) = - (3 y - 4)$
$+ x = y$	$(3 y) = (3 y - 4)$
$- x = y$	$- (3 y) = (3 y - 4)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 3 y \| = \| 3 y - 4 \|$
$x = + y$ , $+ x = y$	$(3 y) = (3 y - 4)$
$x = - y$ , $- x = y$	$(3 y) = - (3 y - 4)$

2. Solve the two equations for y

4 additional steps

$3 y = (3 y - 4)$

Subtract from both sides:

$(3 y) - 3 y = (3 y - 4) - 3 y$

Simplify the arithmetic:

$0 = (3 y - 4) - 3 y$

Group like terms:

$0 = (3 y - 3 y) - 4$

Simplify the arithmetic:

$0 = - 4$

The statement is false:

$0 = - 4$

The equation is false so it has no solution.

8 additional steps

$3 y = - (3 y - 4)$

Expand the parentheses:

$3 y = - 3 y + 4$

Add to both sides:

$(3 y) + 3 y = (- 3 y + 4) + 3 y$

Simplify the arithmetic:

$6 y = (- 3 y + 4) + 3 y$

Group like terms:

$6 y = (- 3 y + 3 y) + 4$

Simplify the arithmetic:

$6 y = 4$

Divide both sides by :

$\frac{(6 y)}{6} = \frac{4}{6}$

Simplify the fraction:

$y = \frac{4}{6}$

Find the greatest common factor of the numerator and denominator:

$y = \frac{(2 \cdot 2)}{(3 \cdot 2)}$

Factor out and cancel the greatest common factor:

$y = \frac{2}{3}$

3. Graph

Each line represents the function of one side of the equation:
$y = | 3 y |$
$y = | 3 y - 4 |$
The equation is true where the two lines cross.

How did we do?

Please leave us feedback.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for y

3. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for y

3. Graph

Why learn this

Terms and topics

Related links

Latest Related Drills Solved