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Solution - Absolute value equations

Exact form: y=3,1
y=3 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3y1|=|y+5|
without the absolute value bars:

|x|=|y||3y1|=|y+5|
x=+y(3y1)=(y+5)
x=y(3y1)=(y+5)
+x=y(3y1)=(y+5)
x=y(3y1)=(y+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3y1|=|y+5|
x=+y , +x=y(3y1)=(y+5)
x=y , x=y(3y1)=(y+5)

2. Solve the two equations for y

11 additional steps

(3y-1)=(y+5)

Subtract from both sides:

(3y-1)-y=(y+5)-y

Group like terms:

(3y-y)-1=(y+5)-y

Simplify the arithmetic:

2y-1=(y+5)-y

Group like terms:

2y-1=(y-y)+5

Simplify the arithmetic:

2y1=5

Add to both sides:

(2y-1)+1=5+1

Simplify the arithmetic:

2y=5+1

Simplify the arithmetic:

2y=6

Divide both sides by :

(2y)2=62

Simplify the fraction:

y=62

Find the greatest common factor of the numerator and denominator:

y=(3·2)(1·2)

Factor out and cancel the greatest common factor:

y=3

11 additional steps

(3y-1)=-(y+5)

Expand the parentheses:

(3y-1)=-y-5

Add to both sides:

(3y-1)+y=(-y-5)+y

Group like terms:

(3y+y)-1=(-y-5)+y

Simplify the arithmetic:

4y-1=(-y-5)+y

Group like terms:

4y-1=(-y+y)-5

Simplify the arithmetic:

4y1=5

Add to both sides:

(4y-1)+1=-5+1

Simplify the arithmetic:

4y=5+1

Simplify the arithmetic:

4y=4

Divide both sides by :

(4y)4=-44

Simplify the fraction:

y=-44

Simplify the fraction:

y=1

3. List the solutions

y=3,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3y1|
y=|y+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.