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Solution - Absolute value equations

Exact form: y=-2,-32
y=-2 , -\frac{3}{2}
Mixed number form: y=-2,-112
y=-2 , -1\frac{1}{2}
Decimal form: y=2,1.5
y=-2 , -1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3y+5|=|y+1|
without the absolute value bars:

|x|=|y||3y+5|=|y+1|
x=+y(3y+5)=(y+1)
x=y(3y+5)=(y+1)
+x=y(3y+5)=(y+1)
x=y(3y+5)=(y+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3y+5|=|y+1|
x=+y , +x=y(3y+5)=(y+1)
x=y , x=y(3y+5)=(y+1)

2. Solve the two equations for y

11 additional steps

(3y+5)=(y+1)

Subtract from both sides:

(3y+5)-y=(y+1)-y

Group like terms:

(3y-y)+5=(y+1)-y

Simplify the arithmetic:

2y+5=(y+1)-y

Group like terms:

2y+5=(y-y)+1

Simplify the arithmetic:

2y+5=1

Subtract from both sides:

(2y+5)-5=1-5

Simplify the arithmetic:

2y=15

Simplify the arithmetic:

2y=4

Divide both sides by :

(2y)2=-42

Simplify the fraction:

y=-42

Find the greatest common factor of the numerator and denominator:

y=(-2·2)(1·2)

Factor out and cancel the greatest common factor:

y=2

12 additional steps

(3y+5)=-(y+1)

Expand the parentheses:

(3y+5)=-y-1

Add to both sides:

(3y+5)+y=(-y-1)+y

Group like terms:

(3y+y)+5=(-y-1)+y

Simplify the arithmetic:

4y+5=(-y-1)+y

Group like terms:

4y+5=(-y+y)-1

Simplify the arithmetic:

4y+5=1

Subtract from both sides:

(4y+5)-5=-1-5

Simplify the arithmetic:

4y=15

Simplify the arithmetic:

4y=6

Divide both sides by :

(4y)4=-64

Simplify the fraction:

y=-64

Find the greatest common factor of the numerator and denominator:

y=(-3·2)(2·2)

Factor out and cancel the greatest common factor:

y=-32

3. List the solutions

y=-2,-32
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3y+5|
y=|y+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.