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Solution - Absolute value equations

Exact form: y=14,-52
y=\frac{1}{4} , -\frac{5}{2}
Mixed number form: y=14,-212
y=\frac{1}{4} , -2\frac{1}{2}
Decimal form: y=0.25,2.5
y=0.25 , -2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3y+2|=|y+3|
without the absolute value bars:

|x|=|y||3y+2|=|y+3|
x=+y(3y+2)=(y+3)
x=y(3y+2)=(y+3)
+x=y(3y+2)=(y+3)
x=y(3y+2)=(y+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3y+2|=|y+3|
x=+y , +x=y(3y+2)=(y+3)
x=y , x=y(3y+2)=(y+3)

2. Solve the two equations for y

9 additional steps

(3y+2)=(-y+3)

Add to both sides:

(3y+2)+y=(-y+3)+y

Group like terms:

(3y+y)+2=(-y+3)+y

Simplify the arithmetic:

4y+2=(-y+3)+y

Group like terms:

4y+2=(-y+y)+3

Simplify the arithmetic:

4y+2=3

Subtract from both sides:

(4y+2)-2=3-2

Simplify the arithmetic:

4y=32

Simplify the arithmetic:

4y=1

Divide both sides by :

(4y)4=14

Simplify the fraction:

y=14

10 additional steps

(3y+2)=-(-y+3)

Expand the parentheses:

(3y+2)=y-3

Subtract from both sides:

(3y+2)-y=(y-3)-y

Group like terms:

(3y-y)+2=(y-3)-y

Simplify the arithmetic:

2y+2=(y-3)-y

Group like terms:

2y+2=(y-y)-3

Simplify the arithmetic:

2y+2=3

Subtract from both sides:

(2y+2)-2=-3-2

Simplify the arithmetic:

2y=32

Simplify the arithmetic:

2y=5

Divide both sides by :

(2y)2=-52

Simplify the fraction:

y=-52

3. List the solutions

y=14,-52
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3y+2|
y=|y+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.