Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-56,1312
x=-\frac{5}{6} , \frac{13}{12}
Mixed number form: x=-56,1112
x=-\frac{5}{6} , 1\frac{1}{12}
Decimal form: x=0.833,1.083
x=-0.833 , 1.083

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x9|=|9x4|
without the absolute value bars:

|x|=|y||3x9|=|9x4|
x=+y(3x9)=(9x4)
x=y(3x9)=(9x4)
+x=y(3x9)=(9x4)
x=y(3x9)=(9x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x9|=|9x4|
x=+y , +x=y(3x9)=(9x4)
x=y , x=y(3x9)=(9x4)

2. Solve the two equations for x

11 additional steps

(3x-9)=(9x-4)

Subtract from both sides:

(3x-9)-9x=(9x-4)-9x

Group like terms:

(3x-9x)-9=(9x-4)-9x

Simplify the arithmetic:

-6x-9=(9x-4)-9x

Group like terms:

-6x-9=(9x-9x)-4

Simplify the arithmetic:

6x9=4

Add to both sides:

(-6x-9)+9=-4+9

Simplify the arithmetic:

6x=4+9

Simplify the arithmetic:

6x=5

Divide both sides by :

(-6x)-6=5-6

Cancel out the negatives:

6x6=5-6

Simplify the fraction:

x=5-6

Move the negative sign from the denominator to the numerator:

x=-56

10 additional steps

(3x-9)=-(9x-4)

Expand the parentheses:

(3x-9)=-9x+4

Add to both sides:

(3x-9)+9x=(-9x+4)+9x

Group like terms:

(3x+9x)-9=(-9x+4)+9x

Simplify the arithmetic:

12x-9=(-9x+4)+9x

Group like terms:

12x-9=(-9x+9x)+4

Simplify the arithmetic:

12x9=4

Add to both sides:

(12x-9)+9=4+9

Simplify the arithmetic:

12x=4+9

Simplify the arithmetic:

12x=13

Divide both sides by :

(12x)12=1312

Simplify the fraction:

x=1312

3. List the solutions

x=-56,1312
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x9|
y=|9x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.