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Solution - Absolute value equations

Exact form: x=-6,-29
x=-6 , -\frac{2}{9}
Decimal form: x=6,0.222
x=-6 , -0.222

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x8|=|6x+10|
without the absolute value bars:

|x|=|y||3x8|=|6x+10|
x=+y(3x8)=(6x+10)
x=y(3x8)=(6x+10)
+x=y(3x8)=(6x+10)
x=y(3x8)=(6x+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x8|=|6x+10|
x=+y , +x=y(3x8)=(6x+10)
x=y , x=y(3x8)=(6x+10)

2. Solve the two equations for x

13 additional steps

(3x-8)=(6x+10)

Subtract from both sides:

(3x-8)-6x=(6x+10)-6x

Group like terms:

(3x-6x)-8=(6x+10)-6x

Simplify the arithmetic:

-3x-8=(6x+10)-6x

Group like terms:

-3x-8=(6x-6x)+10

Simplify the arithmetic:

3x8=10

Add to both sides:

(-3x-8)+8=10+8

Simplify the arithmetic:

3x=10+8

Simplify the arithmetic:

3x=18

Divide both sides by :

(-3x)-3=18-3

Cancel out the negatives:

3x3=18-3

Simplify the fraction:

x=18-3

Move the negative sign from the denominator to the numerator:

x=-183

Find the greatest common factor of the numerator and denominator:

x=(-6·3)(1·3)

Factor out and cancel the greatest common factor:

x=6

10 additional steps

(3x-8)=-(6x+10)

Expand the parentheses:

(3x-8)=-6x-10

Add to both sides:

(3x-8)+6x=(-6x-10)+6x

Group like terms:

(3x+6x)-8=(-6x-10)+6x

Simplify the arithmetic:

9x-8=(-6x-10)+6x

Group like terms:

9x-8=(-6x+6x)-10

Simplify the arithmetic:

9x8=10

Add to both sides:

(9x-8)+8=-10+8

Simplify the arithmetic:

9x=10+8

Simplify the arithmetic:

9x=2

Divide both sides by :

(9x)9=-29

Simplify the fraction:

x=-29

3. List the solutions

x=-6,-29
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x8|
y=|6x+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.