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Solution - Absolute value equations

Exact form: x=135,3
x=\frac{13}{5} , 3
Mixed number form: x=235,3
x=2\frac{3}{5} , 3
Decimal form: x=2.6,3
x=2.6 , 3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x8|=|2x+5|
without the absolute value bars:

|x|=|y||3x8|=|2x+5|
x=+y(3x8)=(2x+5)
x=y(3x8)=(2x+5)
+x=y(3x8)=(2x+5)
x=y(3x8)=(2x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x8|=|2x+5|
x=+y , +x=y(3x8)=(2x+5)
x=y , x=y(3x8)=(2x+5)

2. Solve the two equations for x

9 additional steps

(3x-8)=(-2x+5)

Add to both sides:

(3x-8)+2x=(-2x+5)+2x

Group like terms:

(3x+2x)-8=(-2x+5)+2x

Simplify the arithmetic:

5x-8=(-2x+5)+2x

Group like terms:

5x-8=(-2x+2x)+5

Simplify the arithmetic:

5x8=5

Add to both sides:

(5x-8)+8=5+8

Simplify the arithmetic:

5x=5+8

Simplify the arithmetic:

5x=13

Divide both sides by :

(5x)5=135

Simplify the fraction:

x=135

8 additional steps

(3x-8)=-(-2x+5)

Expand the parentheses:

(3x-8)=2x-5

Subtract from both sides:

(3x-8)-2x=(2x-5)-2x

Group like terms:

(3x-2x)-8=(2x-5)-2x

Simplify the arithmetic:

x-8=(2x-5)-2x

Group like terms:

x-8=(2x-2x)-5

Simplify the arithmetic:

x8=5

Add to both sides:

(x-8)+8=-5+8

Simplify the arithmetic:

x=5+8

Simplify the arithmetic:

x=3

3. List the solutions

x=135,3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x8|
y=|2x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.