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Solution - Absolute value equations

Exact form: x=-23
x=-\frac{2}{3}
Decimal form: x=0.667
x=-0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x7|=|3x+11|
without the absolute value bars:

|x|=|y||3x7|=|3x+11|
x=+y(3x7)=(3x+11)
x=y(3x7)=(3x+11)
+x=y(3x7)=(3x+11)
x=y(3x7)=(3x+11)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x7|=|3x+11|
x=+y , +x=y(3x7)=(3x+11)
x=y , x=y(3x7)=(3x+11)

2. Solve the two equations for x

5 additional steps

(3x-7)=(3x+11)

Subtract from both sides:

(3x-7)-3x=(3x+11)-3x

Group like terms:

(3x-3x)-7=(3x+11)-3x

Simplify the arithmetic:

-7=(3x+11)-3x

Group like terms:

-7=(3x-3x)+11

Simplify the arithmetic:

7=11

The statement is false:

7=11

The equation is false so it has no solution.

12 additional steps

(3x-7)=-(3x+11)

Expand the parentheses:

(3x-7)=-3x-11

Add to both sides:

(3x-7)+3x=(-3x-11)+3x

Group like terms:

(3x+3x)-7=(-3x-11)+3x

Simplify the arithmetic:

6x-7=(-3x-11)+3x

Group like terms:

6x-7=(-3x+3x)-11

Simplify the arithmetic:

6x7=11

Add to both sides:

(6x-7)+7=-11+7

Simplify the arithmetic:

6x=11+7

Simplify the arithmetic:

6x=4

Divide both sides by :

(6x)6=-46

Simplify the fraction:

x=-46

Find the greatest common factor of the numerator and denominator:

x=(-2·2)(3·2)

Factor out and cancel the greatest common factor:

x=-23

3. Graph

Each line represents the function of one side of the equation:
y=|3x7|
y=|3x+11|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.