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Solution - Absolute value equations

Exact form: x=-32
x=-\frac{3}{2}
Mixed number form: x=-112
x=-1\frac{1}{2}
Decimal form: x=1.5
x=-1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x6|+|3x+15|=0

Add |3x+15| to both sides of the equation:

|3x6|+|3x+15||3x+15|=|3x+15|

Simplify the arithmetic

|3x6|=|3x+15|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x6|=|3x+15|
without the absolute value bars:

|x|=|y||3x6|=|3x+15|
x=+y(3x6)=(3x+15)
x=y(3x6)=(3x+15)
+x=y(3x6)=(3x+15)
x=y(3x6)=(3x+15)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x6|=|3x+15|
x=+y , +x=y(3x6)=(3x+15)
x=y , x=y(3x6)=(3x+15)

3. Solve the two equations for x

12 additional steps

(3x-6)=-(3x+15)

Expand the parentheses:

(3x-6)=-3x-15

Add to both sides:

(3x-6)+3x=(-3x-15)+3x

Group like terms:

(3x+3x)-6=(-3x-15)+3x

Simplify the arithmetic:

6x-6=(-3x-15)+3x

Group like terms:

6x-6=(-3x+3x)-15

Simplify the arithmetic:

6x6=15

Add to both sides:

(6x-6)+6=-15+6

Simplify the arithmetic:

6x=15+6

Simplify the arithmetic:

6x=9

Divide both sides by :

(6x)6=-96

Simplify the fraction:

x=-96

Find the greatest common factor of the numerator and denominator:

x=(-3·3)(2·3)

Factor out and cancel the greatest common factor:

x=-32

6 additional steps

(3x-6)=-(-(3x+15))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(3x-6)=3x+15

Subtract from both sides:

(3x-6)-3x=(3x+15)-3x

Group like terms:

(3x-3x)-6=(3x+15)-3x

Simplify the arithmetic:

-6=(3x+15)-3x

Group like terms:

-6=(3x-3x)+15

Simplify the arithmetic:

6=15

The statement is false:

6=15

The equation is false so it has no solution.

4. List the solutions

x=-32
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3x6|
y=|3x+15|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.