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Solution - Absolute value equations

Exact form: x=12,40
x=12 , 40

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x50|=|2x+10|
without the absolute value bars:

|x|=|y||3x50|=|2x+10|
x=+y(3x50)=(2x+10)
x=y(3x50)=(2x+10)
+x=y(3x50)=(2x+10)
x=y(3x50)=(2x+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x50|=|2x+10|
x=+y , +x=y(3x50)=(2x+10)
x=y , x=y(3x50)=(2x+10)

2. Solve the two equations for x

11 additional steps

(3x-50)=(-2x+10)

Add to both sides:

(3x-50)+2x=(-2x+10)+2x

Group like terms:

(3x+2x)-50=(-2x+10)+2x

Simplify the arithmetic:

5x-50=(-2x+10)+2x

Group like terms:

5x-50=(-2x+2x)+10

Simplify the arithmetic:

5x50=10

Add to both sides:

(5x-50)+50=10+50

Simplify the arithmetic:

5x=10+50

Simplify the arithmetic:

5x=60

Divide both sides by :

(5x)5=605

Simplify the fraction:

x=605

Find the greatest common factor of the numerator and denominator:

x=(12·5)(1·5)

Factor out and cancel the greatest common factor:

x=12

8 additional steps

(3x-50)=-(-2x+10)

Expand the parentheses:

(3x-50)=2x-10

Subtract from both sides:

(3x-50)-2x=(2x-10)-2x

Group like terms:

(3x-2x)-50=(2x-10)-2x

Simplify the arithmetic:

x-50=(2x-10)-2x

Group like terms:

x-50=(2x-2x)-10

Simplify the arithmetic:

x50=10

Add to both sides:

(x-50)+50=-10+50

Simplify the arithmetic:

x=10+50

Simplify the arithmetic:

x=40

3. List the solutions

x=12,40
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x50|
y=|2x+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.