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Solution - Absolute value equations

Exact form: x=-125,-211
x=-\frac{12}{5} , -\frac{2}{11}
Mixed number form: x=-225,-211
x=-2\frac{2}{5} , -\frac{2}{11}
Decimal form: x=2.4,0.182
x=-2.4 , -0.182

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x5|=|8x+7|
without the absolute value bars:

|x|=|y||3x5|=|8x+7|
x=+y(3x5)=(8x+7)
x=y(3x5)=(8x+7)
+x=y(3x5)=(8x+7)
x=y(3x5)=(8x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x5|=|8x+7|
x=+y , +x=y(3x5)=(8x+7)
x=y , x=y(3x5)=(8x+7)

2. Solve the two equations for x

11 additional steps

(3x-5)=(8x+7)

Subtract from both sides:

(3x-5)-8x=(8x+7)-8x

Group like terms:

(3x-8x)-5=(8x+7)-8x

Simplify the arithmetic:

-5x-5=(8x+7)-8x

Group like terms:

-5x-5=(8x-8x)+7

Simplify the arithmetic:

5x5=7

Add to both sides:

(-5x-5)+5=7+5

Simplify the arithmetic:

5x=7+5

Simplify the arithmetic:

5x=12

Divide both sides by :

(-5x)-5=12-5

Cancel out the negatives:

5x5=12-5

Simplify the fraction:

x=12-5

Move the negative sign from the denominator to the numerator:

x=-125

10 additional steps

(3x-5)=-(8x+7)

Expand the parentheses:

(3x-5)=-8x-7

Add to both sides:

(3x-5)+8x=(-8x-7)+8x

Group like terms:

(3x+8x)-5=(-8x-7)+8x

Simplify the arithmetic:

11x-5=(-8x-7)+8x

Group like terms:

11x-5=(-8x+8x)-7

Simplify the arithmetic:

11x5=7

Add to both sides:

(11x-5)+5=-7+5

Simplify the arithmetic:

11x=7+5

Simplify the arithmetic:

11x=2

Divide both sides by :

(11x)11=-211

Simplify the fraction:

x=-211

3. List the solutions

x=-125,-211
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x5|
y=|8x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.