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Solution - Absolute value equations

Exact form: x=-167,-613
x=-\frac{16}{7} , -\frac{6}{13}
Mixed number form: x=-227,-613
x=-2\frac{2}{7} , -\frac{6}{13}
Decimal form: x=2.286,0.462
x=-2.286 , -0.462

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x5|=|10x+11|
without the absolute value bars:

|x|=|y||3x5|=|10x+11|
x=+y(3x5)=(10x+11)
x=y(3x5)=(10x+11)
+x=y(3x5)=(10x+11)
x=y(3x5)=(10x+11)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x5|=|10x+11|
x=+y , +x=y(3x5)=(10x+11)
x=y , x=y(3x5)=(10x+11)

2. Solve the two equations for x

11 additional steps

(3x-5)=(10x+11)

Subtract from both sides:

(3x-5)-10x=(10x+11)-10x

Group like terms:

(3x-10x)-5=(10x+11)-10x

Simplify the arithmetic:

-7x-5=(10x+11)-10x

Group like terms:

-7x-5=(10x-10x)+11

Simplify the arithmetic:

7x5=11

Add to both sides:

(-7x-5)+5=11+5

Simplify the arithmetic:

7x=11+5

Simplify the arithmetic:

7x=16

Divide both sides by :

(-7x)-7=16-7

Cancel out the negatives:

7x7=16-7

Simplify the fraction:

x=16-7

Move the negative sign from the denominator to the numerator:

x=-167

10 additional steps

(3x-5)=-(10x+11)

Expand the parentheses:

(3x-5)=-10x-11

Add to both sides:

(3x-5)+10x=(-10x-11)+10x

Group like terms:

(3x+10x)-5=(-10x-11)+10x

Simplify the arithmetic:

13x-5=(-10x-11)+10x

Group like terms:

13x-5=(-10x+10x)-11

Simplify the arithmetic:

13x5=11

Add to both sides:

(13x-5)+5=-11+5

Simplify the arithmetic:

13x=11+5

Simplify the arithmetic:

13x=6

Divide both sides by :

(13x)13=-613

Simplify the fraction:

x=-613

3. List the solutions

x=-167,-613
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x5|
y=|10x+11|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.