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Solution - Absolute value equations

Exact form: x=5,3
x=-5 , 3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x45|=|12x|
without the absolute value bars:

|x|=|y||3x45|=|12x|
x=+y(3x45)=(12x)
x=y(3x45)=(12x)
+x=y(3x45)=(12x)
x=y(3x45)=(12x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x45|=|12x|
x=+y , +x=y(3x45)=(12x)
x=y , x=y(3x45)=(12x)

2. Solve the two equations for x

12 additional steps

(3x-45)=12x

Subtract from both sides:

(3x-45)-12x=(12x)-12x

Group like terms:

(3x-12x)-45=(12x)-12x

Simplify the arithmetic:

-9x-45=(12x)-12x

Simplify the arithmetic:

9x45=0

Add to both sides:

(-9x-45)+45=0+45

Simplify the arithmetic:

9x=0+45

Simplify the arithmetic:

9x=45

Divide both sides by :

(-9x)-9=45-9

Cancel out the negatives:

9x9=45-9

Simplify the fraction:

x=45-9

Move the negative sign from the denominator to the numerator:

x=-459

Find the greatest common factor of the numerator and denominator:

x=(-5·9)(1·9)

Factor out and cancel the greatest common factor:

x=5

9 additional steps

(3x-45)=-12x

Add to both sides:

(3x-45)+45=(-12x)+45

Simplify the arithmetic:

3x=(-12x)+45

Add to both sides:

(3x)+12x=((-12x)+45)+12x

Simplify the arithmetic:

15x=((-12x)+45)+12x

Group like terms:

15x=(-12x+12x)+45

Simplify the arithmetic:

15x=45

Divide both sides by :

(15x)15=4515

Simplify the fraction:

x=4515

Find the greatest common factor of the numerator and denominator:

x=(3·15)(1·15)

Factor out and cancel the greatest common factor:

x=3

3. List the solutions

x=5,3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x45|
y=|12x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.