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Solution - Absolute value equations

Exact form: x=54,1
x=\frac{5}{4} , 1
Mixed number form: x=114,1
x=1\frac{1}{4} , 1
Decimal form: x=1.25,1
x=1.25 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x4|=|5x+6|
without the absolute value bars:

|x|=|y||3x4|=|5x+6|
x=+y(3x4)=(5x+6)
x=y(3x4)=(5x+6)
+x=y(3x4)=(5x+6)
x=y(3x4)=(5x+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x4|=|5x+6|
x=+y , +x=y(3x4)=(5x+6)
x=y , x=y(3x4)=(5x+6)

2. Solve the two equations for x

11 additional steps

(3x-4)=(-5x+6)

Add to both sides:

(3x-4)+5x=(-5x+6)+5x

Group like terms:

(3x+5x)-4=(-5x+6)+5x

Simplify the arithmetic:

8x-4=(-5x+6)+5x

Group like terms:

8x-4=(-5x+5x)+6

Simplify the arithmetic:

8x4=6

Add to both sides:

(8x-4)+4=6+4

Simplify the arithmetic:

8x=6+4

Simplify the arithmetic:

8x=10

Divide both sides by :

(8x)8=108

Simplify the fraction:

x=108

Find the greatest common factor of the numerator and denominator:

x=(5·2)(4·2)

Factor out and cancel the greatest common factor:

x=54

13 additional steps

(3x-4)=-(-5x+6)

Expand the parentheses:

(3x-4)=5x-6

Subtract from both sides:

(3x-4)-5x=(5x-6)-5x

Group like terms:

(3x-5x)-4=(5x-6)-5x

Simplify the arithmetic:

-2x-4=(5x-6)-5x

Group like terms:

-2x-4=(5x-5x)-6

Simplify the arithmetic:

2x4=6

Add to both sides:

(-2x-4)+4=-6+4

Simplify the arithmetic:

2x=6+4

Simplify the arithmetic:

2x=2

Divide both sides by :

(-2x)-2=-2-2

Cancel out the negatives:

2x2=-2-2

Simplify the fraction:

x=-2-2

Cancel out the negatives:

x=22

Simplify the fraction:

x=1

3. List the solutions

x=54,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x4|
y=|5x+6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.