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Solution - Absolute value equations

Exact form: x=-87,0
x=-\frac{8}{7} , 0
Mixed number form: x=-117,0
x=-1\frac{1}{7} , 0
Decimal form: x=1.143,0
x=-1.143 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x4|=|10x+4|
without the absolute value bars:

|x|=|y||3x4|=|10x+4|
x=+y(3x4)=(10x+4)
x=y(3x4)=(10x+4)
+x=y(3x4)=(10x+4)
x=y(3x4)=(10x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x4|=|10x+4|
x=+y , +x=y(3x4)=(10x+4)
x=y , x=y(3x4)=(10x+4)

2. Solve the two equations for x

11 additional steps

(3x-4)=(10x+4)

Subtract from both sides:

(3x-4)-10x=(10x+4)-10x

Group like terms:

(3x-10x)-4=(10x+4)-10x

Simplify the arithmetic:

-7x-4=(10x+4)-10x

Group like terms:

-7x-4=(10x-10x)+4

Simplify the arithmetic:

7x4=4

Add to both sides:

(-7x-4)+4=4+4

Simplify the arithmetic:

7x=4+4

Simplify the arithmetic:

7x=8

Divide both sides by :

(-7x)-7=8-7

Cancel out the negatives:

7x7=8-7

Simplify the fraction:

x=8-7

Move the negative sign from the denominator to the numerator:

x=-87

9 additional steps

(3x-4)=-(10x+4)

Expand the parentheses:

(3x-4)=-10x-4

Add to both sides:

(3x-4)+10x=(-10x-4)+10x

Group like terms:

(3x+10x)-4=(-10x-4)+10x

Simplify the arithmetic:

13x-4=(-10x-4)+10x

Group like terms:

13x-4=(-10x+10x)-4

Simplify the arithmetic:

13x4=4

Add to both sides:

(13x-4)+4=-4+4

Simplify the arithmetic:

13x=4+4

Simplify the arithmetic:

13x=0

Divide both sides by the coefficient:

x=0

3. List the solutions

x=-87,0
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x4|
y=|10x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.