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Solution - Absolute value equations

Exact form: x=-3,115
x=-3 , \frac{11}{5}
Mixed number form: x=-3,215
x=-3 , 2\frac{1}{5}
Decimal form: x=3,2.2
x=-3 , 2.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x4|+|2x+7|=0

Add |2x+7| to both sides of the equation:

|3x4|+|2x+7||2x+7|=|2x+7|

Simplify the arithmetic

|3x4|=|2x+7|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x4|=|2x+7|
without the absolute value bars:

|x|=|y||3x4|=|2x+7|
x=+y(3x4)=(2x+7)
x=y(3x4)=(2x+7)
+x=y(3x4)=(2x+7)
x=y(3x4)=(2x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x4|=|2x+7|
x=+y , +x=y(3x4)=(2x+7)
x=y , x=y(3x4)=(2x+7)

3. Solve the two equations for x

8 additional steps

(3x-4)=-(-2x+7)

Expand the parentheses:

(3x-4)=2x-7

Subtract from both sides:

(3x-4)-2x=(2x-7)-2x

Group like terms:

(3x-2x)-4=(2x-7)-2x

Simplify the arithmetic:

x-4=(2x-7)-2x

Group like terms:

x-4=(2x-2x)-7

Simplify the arithmetic:

x4=7

Add to both sides:

(x-4)+4=-7+4

Simplify the arithmetic:

x=7+4

Simplify the arithmetic:

x=3

10 additional steps

(3x-4)=-(-(-2x+7))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(3x-4)=-2x+7

Add to both sides:

(3x-4)+2x=(-2x+7)+2x

Group like terms:

(3x+2x)-4=(-2x+7)+2x

Simplify the arithmetic:

5x-4=(-2x+7)+2x

Group like terms:

5x-4=(-2x+2x)+7

Simplify the arithmetic:

5x4=7

Add to both sides:

(5x-4)+4=7+4

Simplify the arithmetic:

5x=7+4

Simplify the arithmetic:

5x=11

Divide both sides by :

(5x)5=115

Simplify the fraction:

x=115

4. List the solutions

x=-3,115
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3x4|
y=|2x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.