Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=5,15
x=5 , \frac{1}{5}
Decimal form: x=5,0.2
x=5 , 0.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x3||2x+2|=0

Add |2x+2| to both sides of the equation:

|3x3||2x+2|+|2x+2|=|2x+2|

Simplify the arithmetic

|3x3|=|2x+2|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x3|=|2x+2|
without the absolute value bars:

|x|=|y||3x3|=|2x+2|
x=+y(3x3)=(2x+2)
x=y(3x3)=((2x+2))
+x=y(3x3)=(2x+2)
x=y(3x3)=(2x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x3|=|2x+2|
x=+y , +x=y(3x3)=(2x+2)
x=y , x=y(3x3)=((2x+2))

3. Solve the two equations for x

7 additional steps

(3x-3)=(2x+2)

Subtract from both sides:

(3x-3)-2x=(2x+2)-2x

Group like terms:

(3x-2x)-3=(2x+2)-2x

Simplify the arithmetic:

x-3=(2x+2)-2x

Group like terms:

x-3=(2x-2x)+2

Simplify the arithmetic:

x3=2

Add to both sides:

(x-3)+3=2+3

Simplify the arithmetic:

x=2+3

Simplify the arithmetic:

x=5

10 additional steps

(3x-3)=-(2x+2)

Expand the parentheses:

(3x-3)=-2x-2

Add to both sides:

(3x-3)+2x=(-2x-2)+2x

Group like terms:

(3x+2x)-3=(-2x-2)+2x

Simplify the arithmetic:

5x-3=(-2x-2)+2x

Group like terms:

5x-3=(-2x+2x)-2

Simplify the arithmetic:

5x3=2

Add to both sides:

(5x-3)+3=-2+3

Simplify the arithmetic:

5x=2+3

Simplify the arithmetic:

5x=1

Divide both sides by :

(5x)5=15

Simplify the fraction:

x=15

4. List the solutions

x=5,15
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3x3|
y=|2x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.