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Solution - Absolute value equations

Exact form: x=4,22
x=4 , 22

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x3|=|4x+25|
without the absolute value bars:

|x|=|y||3x3|=|4x+25|
x=+y(3x3)=(4x+25)
x=y(3x3)=(4x+25)
+x=y(3x3)=(4x+25)
x=y(3x3)=(4x+25)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x3|=|4x+25|
x=+y , +x=y(3x3)=(4x+25)
x=y , x=y(3x3)=(4x+25)

2. Solve the two equations for x

11 additional steps

(3x-3)=(-4x+25)

Add to both sides:

(3x-3)+4x=(-4x+25)+4x

Group like terms:

(3x+4x)-3=(-4x+25)+4x

Simplify the arithmetic:

7x-3=(-4x+25)+4x

Group like terms:

7x-3=(-4x+4x)+25

Simplify the arithmetic:

7x3=25

Add to both sides:

(7x-3)+3=25+3

Simplify the arithmetic:

7x=25+3

Simplify the arithmetic:

7x=28

Divide both sides by :

(7x)7=287

Simplify the fraction:

x=287

Find the greatest common factor of the numerator and denominator:

x=(4·7)(1·7)

Factor out and cancel the greatest common factor:

x=4

11 additional steps

(3x-3)=-(-4x+25)

Expand the parentheses:

(3x-3)=4x-25

Subtract from both sides:

(3x-3)-4x=(4x-25)-4x

Group like terms:

(3x-4x)-3=(4x-25)-4x

Simplify the arithmetic:

-x-3=(4x-25)-4x

Group like terms:

-x-3=(4x-4x)-25

Simplify the arithmetic:

x3=25

Add to both sides:

(-x-3)+3=-25+3

Simplify the arithmetic:

x=25+3

Simplify the arithmetic:

x=22

Multiply both sides by :

-x·-1=-22·-1

Remove the one(s):

x=-22·-1

Simplify the arithmetic:

x=22

3. List the solutions

x=4,22
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x3|
y=|4x+25|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.