Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=92,-54
x=\frac{9}{2} , -\frac{5}{4}
Mixed number form: x=412,-114
x=4\frac{1}{2} , -1\frac{1}{4}
Decimal form: x=4.5,1.25
x=4.5 , -1.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x2||x+7|=0

Add |x+7| to both sides of the equation:

|3x2||x+7|+|x+7|=|x+7|

Simplify the arithmetic

|3x2|=|x+7|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x2|=|x+7|
without the absolute value bars:

|x|=|y||3x2|=|x+7|
x=+y(3x2)=(x+7)
x=y(3x2)=((x+7))
+x=y(3x2)=(x+7)
x=y(3x2)=(x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x2|=|x+7|
x=+y , +x=y(3x2)=(x+7)
x=y , x=y(3x2)=((x+7))

3. Solve the two equations for x

9 additional steps

(3x-2)=(x+7)

Subtract from both sides:

(3x-2)-x=(x+7)-x

Group like terms:

(3x-x)-2=(x+7)-x

Simplify the arithmetic:

2x-2=(x+7)-x

Group like terms:

2x-2=(x-x)+7

Simplify the arithmetic:

2x2=7

Add to both sides:

(2x-2)+2=7+2

Simplify the arithmetic:

2x=7+2

Simplify the arithmetic:

2x=9

Divide both sides by :

(2x)2=92

Simplify the fraction:

x=92

10 additional steps

(3x-2)=-(x+7)

Expand the parentheses:

(3x-2)=-x-7

Add to both sides:

(3x-2)+x=(-x-7)+x

Group like terms:

(3x+x)-2=(-x-7)+x

Simplify the arithmetic:

4x-2=(-x-7)+x

Group like terms:

4x-2=(-x+x)-7

Simplify the arithmetic:

4x2=7

Add to both sides:

(4x-2)+2=-7+2

Simplify the arithmetic:

4x=7+2

Simplify the arithmetic:

4x=5

Divide both sides by :

(4x)4=-54

Simplify the fraction:

x=-54

4. List the solutions

x=92,-54
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3x2|
y=|x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.