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Solution - Absolute value equations

Exact form: x=32,14
x=\frac{3}{2} , \frac{1}{4}
Mixed number form: x=112,14
x=1\frac{1}{2} , \frac{1}{4}
Decimal form: x=1.5,0.25
x=1.5 , 0.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x2|=|x+1|
without the absolute value bars:

|x|=|y||3x2|=|x+1|
x=+y(3x2)=(x+1)
x=y(3x2)=(x+1)
+x=y(3x2)=(x+1)
x=y(3x2)=(x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x2|=|x+1|
x=+y , +x=y(3x2)=(x+1)
x=y , x=y(3x2)=(x+1)

2. Solve the two equations for x

9 additional steps

(3x-2)=(x+1)

Subtract from both sides:

(3x-2)-x=(x+1)-x

Group like terms:

(3x-x)-2=(x+1)-x

Simplify the arithmetic:

2x-2=(x+1)-x

Group like terms:

2x-2=(x-x)+1

Simplify the arithmetic:

2x2=1

Add to both sides:

(2x-2)+2=1+2

Simplify the arithmetic:

2x=1+2

Simplify the arithmetic:

2x=3

Divide both sides by :

(2x)2=32

Simplify the fraction:

x=32

10 additional steps

(3x-2)=-(x+1)

Expand the parentheses:

(3x-2)=-x-1

Add to both sides:

(3x-2)+x=(-x-1)+x

Group like terms:

(3x+x)-2=(-x-1)+x

Simplify the arithmetic:

4x-2=(-x-1)+x

Group like terms:

4x-2=(-x+x)-1

Simplify the arithmetic:

4x2=1

Add to both sides:

(4x-2)+2=-1+2

Simplify the arithmetic:

4x=1+2

Simplify the arithmetic:

4x=1

Divide both sides by :

(4x)4=14

Simplify the fraction:

x=14

3. List the solutions

x=32,14
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x2|
y=|x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.