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Solution - Absolute value equations

Exact form: x=12,35
x=\frac{1}{2} , \frac{3}{5}
Decimal form: x=0.5,0.6
x=0.5 , 0.6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x2|=|7x4|
without the absolute value bars:

|x|=|y||3x2|=|7x4|
x=+y(3x2)=(7x4)
x=y(3x2)=(7x4)
+x=y(3x2)=(7x4)
x=y(3x2)=(7x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x2|=|7x4|
x=+y , +x=y(3x2)=(7x4)
x=y , x=y(3x2)=(7x4)

2. Solve the two equations for x

13 additional steps

(3x-2)=(7x-4)

Subtract from both sides:

(3x-2)-7x=(7x-4)-7x

Group like terms:

(3x-7x)-2=(7x-4)-7x

Simplify the arithmetic:

-4x-2=(7x-4)-7x

Group like terms:

-4x-2=(7x-7x)-4

Simplify the arithmetic:

4x2=4

Add to both sides:

(-4x-2)+2=-4+2

Simplify the arithmetic:

4x=4+2

Simplify the arithmetic:

4x=2

Divide both sides by :

(-4x)-4=-2-4

Cancel out the negatives:

4x4=-2-4

Simplify the fraction:

x=-2-4

Cancel out the negatives:

x=24

Find the greatest common factor of the numerator and denominator:

x=(1·2)(2·2)

Factor out and cancel the greatest common factor:

x=12

12 additional steps

(3x-2)=-(7x-4)

Expand the parentheses:

(3x-2)=-7x+4

Add to both sides:

(3x-2)+7x=(-7x+4)+7x

Group like terms:

(3x+7x)-2=(-7x+4)+7x

Simplify the arithmetic:

10x-2=(-7x+4)+7x

Group like terms:

10x-2=(-7x+7x)+4

Simplify the arithmetic:

10x2=4

Add to both sides:

(10x-2)+2=4+2

Simplify the arithmetic:

10x=4+2

Simplify the arithmetic:

10x=6

Divide both sides by :

(10x)10=610

Simplify the fraction:

x=610

Find the greatest common factor of the numerator and denominator:

x=(3·2)(5·2)

Factor out and cancel the greatest common factor:

x=35

3. List the solutions

x=12,35
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x2|
y=|7x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.