Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=35,1
x=\frac{3}{5} , 1
Decimal form: x=0.6,1
x=0.6 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x2|=|2x+1|
without the absolute value bars:

|x|=|y||3x2|=|2x+1|
x=+y(3x2)=(2x+1)
x=y(3x2)=(2x+1)
+x=y(3x2)=(2x+1)
x=y(3x2)=(2x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x2|=|2x+1|
x=+y , +x=y(3x2)=(2x+1)
x=y , x=y(3x2)=(2x+1)

2. Solve the two equations for x

9 additional steps

(3x-2)=(-2x+1)

Add to both sides:

(3x-2)+2x=(-2x+1)+2x

Group like terms:

(3x+2x)-2=(-2x+1)+2x

Simplify the arithmetic:

5x-2=(-2x+1)+2x

Group like terms:

5x-2=(-2x+2x)+1

Simplify the arithmetic:

5x2=1

Add to both sides:

(5x-2)+2=1+2

Simplify the arithmetic:

5x=1+2

Simplify the arithmetic:

5x=3

Divide both sides by :

(5x)5=35

Simplify the fraction:

x=35

8 additional steps

(3x-2)=-(-2x+1)

Expand the parentheses:

(3x-2)=2x-1

Subtract from both sides:

(3x-2)-2x=(2x-1)-2x

Group like terms:

(3x-2x)-2=(2x-1)-2x

Simplify the arithmetic:

x-2=(2x-1)-2x

Group like terms:

x-2=(2x-2x)-1

Simplify the arithmetic:

x2=1

Add to both sides:

(x-2)+2=-1+2

Simplify the arithmetic:

x=1+2

Simplify the arithmetic:

x=1

3. List the solutions

x=35,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x2|
y=|2x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.