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Solution - Absolute value equations

Exact form: x=2
x=-2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x14|=|3x+26|
without the absolute value bars:

|x|=|y||3x14|=|3x+26|
x=+y(3x14)=(3x+26)
x=y(3x14)=(3x+26)
+x=y(3x14)=(3x+26)
x=y(3x14)=(3x+26)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x14|=|3x+26|
x=+y , +x=y(3x14)=(3x+26)
x=y , x=y(3x14)=(3x+26)

2. Solve the two equations for x

5 additional steps

(3x-14)=(3x+26)

Subtract from both sides:

(3x-14)-3x=(3x+26)-3x

Group like terms:

(3x-3x)-14=(3x+26)-3x

Simplify the arithmetic:

-14=(3x+26)-3x

Group like terms:

-14=(3x-3x)+26

Simplify the arithmetic:

14=26

The statement is false:

14=26

The equation is false so it has no solution.

12 additional steps

(3x-14)=-(3x+26)

Expand the parentheses:

(3x-14)=-3x-26

Add to both sides:

(3x-14)+3x=(-3x-26)+3x

Group like terms:

(3x+3x)-14=(-3x-26)+3x

Simplify the arithmetic:

6x-14=(-3x-26)+3x

Group like terms:

6x-14=(-3x+3x)-26

Simplify the arithmetic:

6x14=26

Add to both sides:

(6x-14)+14=-26+14

Simplify the arithmetic:

6x=26+14

Simplify the arithmetic:

6x=12

Divide both sides by :

(6x)6=-126

Simplify the fraction:

x=-126

Find the greatest common factor of the numerator and denominator:

x=(-2·6)(1·6)

Factor out and cancel the greatest common factor:

x=2

3. Graph

Each line represents the function of one side of the equation:
y=|3x14|
y=|3x+26|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.