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Solution - Absolute value equations

Exact form: x=12
x=\frac{1}{2}
Decimal form: x=0.5
x=0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x1||3x2|=0

Add |3x2| to both sides of the equation:

|3x1||3x2|+|3x2|=|3x2|

Simplify the arithmetic

|3x1|=|3x2|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x1|=|3x2|
without the absolute value bars:

|x|=|y||3x1|=|3x2|
x=+y(3x1)=(3x2)
x=y(3x1)=((3x2))
+x=y(3x1)=(3x2)
x=y(3x1)=(3x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x1|=|3x2|
x=+y , +x=y(3x1)=(3x2)
x=y , x=y(3x1)=((3x2))

3. Solve the two equations for x

5 additional steps

(3x-1)=(3x-2)

Subtract from both sides:

(3x-1)-3x=(3x-2)-3x

Group like terms:

(3x-3x)-1=(3x-2)-3x

Simplify the arithmetic:

-1=(3x-2)-3x

Group like terms:

-1=(3x-3x)-2

Simplify the arithmetic:

1=2

The statement is false:

1=2

The equation is false so it has no solution.

12 additional steps

(3x-1)=-(3x-2)

Expand the parentheses:

(3x-1)=-3x+2

Add to both sides:

(3x-1)+3x=(-3x+2)+3x

Group like terms:

(3x+3x)-1=(-3x+2)+3x

Simplify the arithmetic:

6x-1=(-3x+2)+3x

Group like terms:

6x-1=(-3x+3x)+2

Simplify the arithmetic:

6x1=2

Add to both sides:

(6x-1)+1=2+1

Simplify the arithmetic:

6x=2+1

Simplify the arithmetic:

6x=3

Divide both sides by :

(6x)6=36

Simplify the fraction:

x=36

Find the greatest common factor of the numerator and denominator:

x=(1·3)(2·3)

Factor out and cancel the greatest common factor:

x=12

4. Graph

Each line represents the function of one side of the equation:
y=|3x1|
y=|3x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.