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Solution - Absolute value equations

Exact form: x=-53,-13
x=-\frac{5}{3} , -\frac{1}{3}
Mixed number form: x=-123,-13
x=-1\frac{2}{3} , -\frac{1}{3}
Decimal form: x=1.667,0.333
x=-1.667 , -0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x1|=|6x+4|
without the absolute value bars:

|x|=|y||3x1|=|6x+4|
x=+y(3x1)=(6x+4)
x=y(3x1)=(6x+4)
+x=y(3x1)=(6x+4)
x=y(3x1)=(6x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x1|=|6x+4|
x=+y , +x=y(3x1)=(6x+4)
x=y , x=y(3x1)=(6x+4)

2. Solve the two equations for x

11 additional steps

(3x-1)=(6x+4)

Subtract from both sides:

(3x-1)-6x=(6x+4)-6x

Group like terms:

(3x-6x)-1=(6x+4)-6x

Simplify the arithmetic:

-3x-1=(6x+4)-6x

Group like terms:

-3x-1=(6x-6x)+4

Simplify the arithmetic:

3x1=4

Add to both sides:

(-3x-1)+1=4+1

Simplify the arithmetic:

3x=4+1

Simplify the arithmetic:

3x=5

Divide both sides by :

(-3x)-3=5-3

Cancel out the negatives:

3x3=5-3

Simplify the fraction:

x=5-3

Move the negative sign from the denominator to the numerator:

x=-53

12 additional steps

(3x-1)=-(6x+4)

Expand the parentheses:

(3x-1)=-6x-4

Add to both sides:

(3x-1)+6x=(-6x-4)+6x

Group like terms:

(3x+6x)-1=(-6x-4)+6x

Simplify the arithmetic:

9x-1=(-6x-4)+6x

Group like terms:

9x-1=(-6x+6x)-4

Simplify the arithmetic:

9x1=4

Add to both sides:

(9x-1)+1=-4+1

Simplify the arithmetic:

9x=4+1

Simplify the arithmetic:

9x=3

Divide both sides by :

(9x)9=-39

Simplify the fraction:

x=-39

Find the greatest common factor of the numerator and denominator:

x=(-1·3)(3·3)

Factor out and cancel the greatest common factor:

x=-13

3. List the solutions

x=-53,-13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x1|
y=|6x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.