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Solution - Absolute value equations

Exact form: x=3,-112
x=3 , -\frac{11}{2}
Mixed number form: x=3,-512
x=3 , -5\frac{1}{2}
Decimal form: x=3,5.5
x=3 , -5.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+8|=|x+14|
without the absolute value bars:

|x|=|y||3x+8|=|x+14|
x=+y(3x+8)=(x+14)
x=y(3x+8)=(x+14)
+x=y(3x+8)=(x+14)
x=y(3x+8)=(x+14)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+8|=|x+14|
x=+y , +x=y(3x+8)=(x+14)
x=y , x=y(3x+8)=(x+14)

2. Solve the two equations for x

11 additional steps

(3x+8)=(x+14)

Subtract from both sides:

(3x+8)-x=(x+14)-x

Group like terms:

(3x-x)+8=(x+14)-x

Simplify the arithmetic:

2x+8=(x+14)-x

Group like terms:

2x+8=(x-x)+14

Simplify the arithmetic:

2x+8=14

Subtract from both sides:

(2x+8)-8=14-8

Simplify the arithmetic:

2x=148

Simplify the arithmetic:

2x=6

Divide both sides by :

(2x)2=62

Simplify the fraction:

x=62

Find the greatest common factor of the numerator and denominator:

x=(3·2)(1·2)

Factor out and cancel the greatest common factor:

x=3

12 additional steps

(3x+8)=-(x+14)

Expand the parentheses:

(3x+8)=-x-14

Add to both sides:

(3x+8)+x=(-x-14)+x

Group like terms:

(3x+x)+8=(-x-14)+x

Simplify the arithmetic:

4x+8=(-x-14)+x

Group like terms:

4x+8=(-x+x)-14

Simplify the arithmetic:

4x+8=14

Subtract from both sides:

(4x+8)-8=-14-8

Simplify the arithmetic:

4x=148

Simplify the arithmetic:

4x=22

Divide both sides by :

(4x)4=-224

Simplify the fraction:

x=-224

Find the greatest common factor of the numerator and denominator:

x=(-11·2)(2·2)

Factor out and cancel the greatest common factor:

x=-112

3. List the solutions

x=3,-112
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+8|
y=|x+14|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.