Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-511,95
x=-\frac{5}{11} , \frac{9}{5}
Mixed number form: x=-511,145
x=-\frac{5}{11} , 1\frac{4}{5}
Decimal form: x=0.455,1.8
x=-0.455 , 1.8

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+7|=|8x2|
without the absolute value bars:

|x|=|y||3x+7|=|8x2|
x=+y(3x+7)=(8x2)
x=y(3x+7)=((8x2))
+x=y(3x+7)=(8x2)
x=y(3x+7)=(8x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+7|=|8x2|
x=+y , +x=y(3x+7)=(8x2)
x=y , x=y(3x+7)=((8x2))

2. Solve the two equations for x

10 additional steps

(3x+7)=-(8x-2)

Expand the parentheses:

(3x+7)=-8x+2

Add to both sides:

(3x+7)+8x=(-8x+2)+8x

Group like terms:

(3x+8x)+7=(-8x+2)+8x

Simplify the arithmetic:

11x+7=(-8x+2)+8x

Group like terms:

11x+7=(-8x+8x)+2

Simplify the arithmetic:

11x+7=2

Subtract from both sides:

(11x+7)-7=2-7

Simplify the arithmetic:

11x=27

Simplify the arithmetic:

11x=5

Divide both sides by :

(11x)11=-511

Simplify the fraction:

x=-511

12 additional steps

(3x+7)=-(-(8x-2))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(3x+7)=8x-2

Subtract from both sides:

(3x+7)-8x=(8x-2)-8x

Group like terms:

(3x-8x)+7=(8x-2)-8x

Simplify the arithmetic:

-5x+7=(8x-2)-8x

Group like terms:

-5x+7=(8x-8x)-2

Simplify the arithmetic:

5x+7=2

Subtract from both sides:

(-5x+7)-7=-2-7

Simplify the arithmetic:

5x=27

Simplify the arithmetic:

5x=9

Divide both sides by :

(-5x)-5=-9-5

Cancel out the negatives:

5x5=-9-5

Simplify the fraction:

x=-9-5

Cancel out the negatives:

x=95

3. List the solutions

x=-511,95
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+7|
y=|8x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.