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Solution - Absolute value equations

Exact form: x=32,-114
x=\frac{3}{2} , -\frac{11}{4}
Mixed number form: x=112,-234
x=1\frac{1}{2} , -2\frac{3}{4}
Decimal form: x=1.5,2.75
x=1.5 , -2.75

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x+4||x+7|=0

Add |x+7| to both sides of the equation:

|3x+4||x+7|+|x+7|=|x+7|

Simplify the arithmetic

|3x+4|=|x+7|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+4|=|x+7|
without the absolute value bars:

|x|=|y||3x+4|=|x+7|
x=+y(3x+4)=(x+7)
x=y(3x+4)=((x+7))
+x=y(3x+4)=(x+7)
x=y(3x+4)=(x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+4|=|x+7|
x=+y , +x=y(3x+4)=(x+7)
x=y , x=y(3x+4)=((x+7))

3. Solve the two equations for x

9 additional steps

(3x+4)=(x+7)

Subtract from both sides:

(3x+4)-x=(x+7)-x

Group like terms:

(3x-x)+4=(x+7)-x

Simplify the arithmetic:

2x+4=(x+7)-x

Group like terms:

2x+4=(x-x)+7

Simplify the arithmetic:

2x+4=7

Subtract from both sides:

(2x+4)-4=7-4

Simplify the arithmetic:

2x=74

Simplify the arithmetic:

2x=3

Divide both sides by :

(2x)2=32

Simplify the fraction:

x=32

10 additional steps

(3x+4)=-(x+7)

Expand the parentheses:

(3x+4)=-x-7

Add to both sides:

(3x+4)+x=(-x-7)+x

Group like terms:

(3x+x)+4=(-x-7)+x

Simplify the arithmetic:

4x+4=(-x-7)+x

Group like terms:

4x+4=(-x+x)-7

Simplify the arithmetic:

4x+4=7

Subtract from both sides:

(4x+4)-4=-7-4

Simplify the arithmetic:

4x=74

Simplify the arithmetic:

4x=11

Divide both sides by :

(4x)4=-114

Simplify the fraction:

x=-114

4. List the solutions

x=32,-114
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3x+4|
y=|x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.