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Solution - Absolute value equations

Exact form: x=-10,25
x=-10 , \frac{2}{5}
Decimal form: x=10,0.4
x=-10 , 0.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+4|=2|x3|
without the absolute value bars:

|x|=|y||3x+4|=2|x3|
x=+y(3x+4)=2(x3)
x=y(3x+4)=2((x3))
+x=y(3x+4)=2(x3)
x=y(3x+4)=2(x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+4|=2|x3|
x=+y , +x=y(3x+4)=2(x3)
x=y , x=y(3x+4)=2((x3))

2. Solve the two equations for x

9 additional steps

(3x+4)=2·(x-3)

Expand the parentheses:

(3x+4)=2x+2·-3

Simplify the arithmetic:

(3x+4)=2x-6

Subtract from both sides:

(3x+4)-2x=(2x-6)-2x

Group like terms:

(3x-2x)+4=(2x-6)-2x

Simplify the arithmetic:

x+4=(2x-6)-2x

Group like terms:

x+4=(2x-2x)-6

Simplify the arithmetic:

x+4=6

Subtract from both sides:

(x+4)-4=-6-4

Simplify the arithmetic:

x=64

Simplify the arithmetic:

x=10

14 additional steps

(3x+4)=2·(-(x-3))

Expand the parentheses:

(3x+4)=2·(-x+3)

(3x+4)=2·-x+2·3

Group like terms:

(3x+4)=(2·-1)x+2·3

Multiply the coefficients:

(3x+4)=-2x+2·3

Simplify the arithmetic:

(3x+4)=-2x+6

Add to both sides:

(3x+4)+2x=(-2x+6)+2x

Group like terms:

(3x+2x)+4=(-2x+6)+2x

Simplify the arithmetic:

5x+4=(-2x+6)+2x

Group like terms:

5x+4=(-2x+2x)+6

Simplify the arithmetic:

5x+4=6

Subtract from both sides:

(5x+4)-4=6-4

Simplify the arithmetic:

5x=64

Simplify the arithmetic:

5x=2

Divide both sides by :

(5x)5=25

Simplify the fraction:

x=25

3. List the solutions

x=-10,25
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+4|
y=2|x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.