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Solution - Absolute value equations

Exact form: x=4,4
x=4 , -4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+4|=|x+12|
without the absolute value bars:

|x|=|y||3x+4|=|x+12|
x=+y(3x+4)=(x+12)
x=y(3x+4)=(x+12)
+x=y(3x+4)=(x+12)
x=y(3x+4)=(x+12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+4|=|x+12|
x=+y , +x=y(3x+4)=(x+12)
x=y , x=y(3x+4)=(x+12)

2. Solve the two equations for x

11 additional steps

(3x+4)=(x+12)

Subtract from both sides:

(3x+4)-x=(x+12)-x

Group like terms:

(3x-x)+4=(x+12)-x

Simplify the arithmetic:

2x+4=(x+12)-x

Group like terms:

2x+4=(x-x)+12

Simplify the arithmetic:

2x+4=12

Subtract from both sides:

(2x+4)-4=12-4

Simplify the arithmetic:

2x=124

Simplify the arithmetic:

2x=8

Divide both sides by :

(2x)2=82

Simplify the fraction:

x=82

Find the greatest common factor of the numerator and denominator:

x=(4·2)(1·2)

Factor out and cancel the greatest common factor:

x=4

12 additional steps

(3x+4)=-(x+12)

Expand the parentheses:

(3x+4)=-x-12

Add to both sides:

(3x+4)+x=(-x-12)+x

Group like terms:

(3x+x)+4=(-x-12)+x

Simplify the arithmetic:

4x+4=(-x-12)+x

Group like terms:

4x+4=(-x+x)-12

Simplify the arithmetic:

4x+4=12

Subtract from both sides:

(4x+4)-4=-12-4

Simplify the arithmetic:

4x=124

Simplify the arithmetic:

4x=16

Divide both sides by :

(4x)4=-164

Simplify the fraction:

x=-164

Find the greatest common factor of the numerator and denominator:

x=(-4·4)(1·4)

Factor out and cancel the greatest common factor:

x=4

3. List the solutions

x=4,4
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+4|
y=|x+12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.