Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=8,1
x=8 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+4|=|5x12|
without the absolute value bars:

|x|=|y||3x+4|=|5x12|
x=+y(3x+4)=(5x12)
x=y(3x+4)=(5x12)
+x=y(3x+4)=(5x12)
x=y(3x+4)=(5x12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+4|=|5x12|
x=+y , +x=y(3x+4)=(5x12)
x=y , x=y(3x+4)=(5x12)

2. Solve the two equations for x

13 additional steps

(3x+4)=(5x-12)

Subtract from both sides:

(3x+4)-5x=(5x-12)-5x

Group like terms:

(3x-5x)+4=(5x-12)-5x

Simplify the arithmetic:

-2x+4=(5x-12)-5x

Group like terms:

-2x+4=(5x-5x)-12

Simplify the arithmetic:

2x+4=12

Subtract from both sides:

(-2x+4)-4=-12-4

Simplify the arithmetic:

2x=124

Simplify the arithmetic:

2x=16

Divide both sides by :

(-2x)-2=-16-2

Cancel out the negatives:

2x2=-16-2

Simplify the fraction:

x=-16-2

Cancel out the negatives:

x=162

Find the greatest common factor of the numerator and denominator:

x=(8·2)(1·2)

Factor out and cancel the greatest common factor:

x=8

11 additional steps

(3x+4)=-(5x-12)

Expand the parentheses:

(3x+4)=-5x+12

Add to both sides:

(3x+4)+5x=(-5x+12)+5x

Group like terms:

(3x+5x)+4=(-5x+12)+5x

Simplify the arithmetic:

8x+4=(-5x+12)+5x

Group like terms:

8x+4=(-5x+5x)+12

Simplify the arithmetic:

8x+4=12

Subtract from both sides:

(8x+4)-4=12-4

Simplify the arithmetic:

8x=124

Simplify the arithmetic:

8x=8

Divide both sides by :

(8x)8=88

Simplify the fraction:

x=88

Simplify the fraction:

x=1

3. List the solutions

x=8,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+4|
y=|5x12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.