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Solution - Absolute value equations

Exact form: x=2,-85
x=2 , -\frac{8}{5}
Mixed number form: x=2,-135
x=2 , -1\frac{3}{5}
Decimal form: x=2,1.6
x=2 , -1.6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+3|=|2x+5|
without the absolute value bars:

|x|=|y||3x+3|=|2x+5|
x=+y(3x+3)=(2x+5)
x=y(3x+3)=(2x+5)
+x=y(3x+3)=(2x+5)
x=y(3x+3)=(2x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+3|=|2x+5|
x=+y , +x=y(3x+3)=(2x+5)
x=y , x=y(3x+3)=(2x+5)

2. Solve the two equations for x

7 additional steps

(3x+3)=(2x+5)

Subtract from both sides:

(3x+3)-2x=(2x+5)-2x

Group like terms:

(3x-2x)+3=(2x+5)-2x

Simplify the arithmetic:

x+3=(2x+5)-2x

Group like terms:

x+3=(2x-2x)+5

Simplify the arithmetic:

x+3=5

Subtract from both sides:

(x+3)-3=5-3

Simplify the arithmetic:

x=53

Simplify the arithmetic:

x=2

10 additional steps

(3x+3)=-(2x+5)

Expand the parentheses:

(3x+3)=-2x-5

Add to both sides:

(3x+3)+2x=(-2x-5)+2x

Group like terms:

(3x+2x)+3=(-2x-5)+2x

Simplify the arithmetic:

5x+3=(-2x-5)+2x

Group like terms:

5x+3=(-2x+2x)-5

Simplify the arithmetic:

5x+3=5

Subtract from both sides:

(5x+3)-3=-5-3

Simplify the arithmetic:

5x=53

Simplify the arithmetic:

5x=8

Divide both sides by :

(5x)5=-85

Simplify the fraction:

x=-85

3. List the solutions

x=2,-85
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+3|
y=|2x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.