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Solution - Absolute value equations

Exact form: x=-52,14
x=-\frac{5}{2} , \frac{1}{4}
Mixed number form: x=-212,14
x=-2\frac{1}{2} , \frac{1}{4}
Decimal form: x=2.5,0.25
x=-2.5 , 0.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x+2||x3|=0

Add |x3| to both sides of the equation:

|3x+2||x3|+|x3|=|x3|

Simplify the arithmetic

|3x+2|=|x3|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+2|=|x3|
without the absolute value bars:

|x|=|y||3x+2|=|x3|
x=+y(3x+2)=(x3)
x=y(3x+2)=((x3))
+x=y(3x+2)=(x3)
x=y(3x+2)=(x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+2|=|x3|
x=+y , +x=y(3x+2)=(x3)
x=y , x=y(3x+2)=((x3))

3. Solve the two equations for x

9 additional steps

(3x+2)=(x-3)

Subtract from both sides:

(3x+2)-x=(x-3)-x

Group like terms:

(3x-x)+2=(x-3)-x

Simplify the arithmetic:

2x+2=(x-3)-x

Group like terms:

2x+2=(x-x)-3

Simplify the arithmetic:

2x+2=3

Subtract from both sides:

(2x+2)-2=-3-2

Simplify the arithmetic:

2x=32

Simplify the arithmetic:

2x=5

Divide both sides by :

(2x)2=-52

Simplify the fraction:

x=-52

10 additional steps

(3x+2)=-(x-3)

Expand the parentheses:

(3x+2)=-x+3

Add to both sides:

(3x+2)+x=(-x+3)+x

Group like terms:

(3x+x)+2=(-x+3)+x

Simplify the arithmetic:

4x+2=(-x+3)+x

Group like terms:

4x+2=(-x+x)+3

Simplify the arithmetic:

4x+2=3

Subtract from both sides:

(4x+2)-2=3-2

Simplify the arithmetic:

4x=32

Simplify the arithmetic:

4x=1

Divide both sides by :

(4x)4=14

Simplify the fraction:

x=14

4. List the solutions

x=-52,14
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3x+2|
y=|x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.