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Solution - Absolute value equations

Exact form: x=-116
x=-\frac{11}{6}
Mixed number form: x=-156
x=-1\frac{5}{6}
Decimal form: x=1.833
x=-1.833

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x+2||3x9|=0

Add |3x9| to both sides of the equation:

|3x+2||3x9|+|3x9|=|3x9|

Simplify the arithmetic

|3x+2|=|3x9|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+2|=|3x9|
without the absolute value bars:

|x|=|y||3x+2|=|3x9|
x=+y(3x+2)=(3x9)
x=y(3x+2)=((3x9))
+x=y(3x+2)=(3x9)
x=y(3x+2)=(3x9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+2|=|3x9|
x=+y , +x=y(3x+2)=(3x9)
x=y , x=y(3x+2)=((3x9))

3. Solve the two equations for x

9 additional steps

(3x+2)=(-3x-9)

Add to both sides:

(3x+2)+3x=(-3x-9)+3x

Group like terms:

(3x+3x)+2=(-3x-9)+3x

Simplify the arithmetic:

6x+2=(-3x-9)+3x

Group like terms:

6x+2=(-3x+3x)-9

Simplify the arithmetic:

6x+2=9

Subtract from both sides:

(6x+2)-2=-9-2

Simplify the arithmetic:

6x=92

Simplify the arithmetic:

6x=11

Divide both sides by :

(6x)6=-116

Simplify the fraction:

x=-116

6 additional steps

(3x+2)=-(-3x-9)

Expand the parentheses:

(3x+2)=3x+9

Subtract from both sides:

(3x+2)-3x=(3x+9)-3x

Group like terms:

(3x-3x)+2=(3x+9)-3x

Simplify the arithmetic:

2=(3x+9)-3x

Group like terms:

2=(3x-3x)+9

Simplify the arithmetic:

2=9

The statement is false:

2=9

The equation is false so it has no solution.

4. List the solutions

x=-116
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3x+2|
y=|3x9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.