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Solution - Absolute value equations

Exact form: x=-43
x=-\frac{4}{3}
Mixed number form: x=-113
x=-1\frac{1}{3}
Decimal form: x=1.333
x=-1.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+2|=3|x+2|
without the absolute value bars:

|x|=|y||3x+2|=3|x+2|
x=+y(3x+2)=3(x+2)
x=y(3x+2)=3((x+2))
+x=y(3x+2)=3(x+2)
x=y(3x+2)=3(x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+2|=3|x+2|
x=+y , +x=y(3x+2)=3(x+2)
x=y , x=y(3x+2)=3((x+2))

2. Solve the two equations for x

7 additional steps

(3x+2)=3·(x+2)

Expand the parentheses:

(3x+2)=3x+3·2

Simplify the arithmetic:

(3x+2)=3x+6

Subtract from both sides:

(3x+2)-3x=(3x+6)-3x

Group like terms:

(3x-3x)+2=(3x+6)-3x

Simplify the arithmetic:

2=(3x+6)-3x

Group like terms:

2=(3x-3x)+6

Simplify the arithmetic:

2=6

The statement is false:

2=6

The equation is false so it has no solution.

16 additional steps

(3x+2)=3·(-(x+2))

Expand the parentheses:

(3x+2)=3·(-x-2)

(3x+2)=3·-x+3·-2

Group like terms:

(3x+2)=(3·-1)x+3·-2

Multiply the coefficients:

(3x+2)=-3x+3·-2

Simplify the arithmetic:

(3x+2)=-3x-6

Add to both sides:

(3x+2)+3x=(-3x-6)+3x

Group like terms:

(3x+3x)+2=(-3x-6)+3x

Simplify the arithmetic:

6x+2=(-3x-6)+3x

Group like terms:

6x+2=(-3x+3x)-6

Simplify the arithmetic:

6x+2=6

Subtract from both sides:

(6x+2)-2=-6-2

Simplify the arithmetic:

6x=62

Simplify the arithmetic:

6x=8

Divide both sides by :

(6x)6=-86

Simplify the fraction:

x=-86

Find the greatest common factor of the numerator and denominator:

x=(-4·2)(3·2)

Factor out and cancel the greatest common factor:

x=-43

3. Graph

Each line represents the function of one side of the equation:
y=|3x+2|
y=3|x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.