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Solution - Absolute value equations

Exact form: x=4,1
x=-4 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+2|=|x6|
without the absolute value bars:

|x|=|y||3x+2|=|x6|
x=+y(3x+2)=(x6)
x=y(3x+2)=(x6)
+x=y(3x+2)=(x6)
x=y(3x+2)=(x6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+2|=|x6|
x=+y , +x=y(3x+2)=(x6)
x=y , x=y(3x+2)=(x6)

2. Solve the two equations for x

11 additional steps

(3x+2)=(x-6)

Subtract from both sides:

(3x+2)-x=(x-6)-x

Group like terms:

(3x-x)+2=(x-6)-x

Simplify the arithmetic:

2x+2=(x-6)-x

Group like terms:

2x+2=(x-x)-6

Simplify the arithmetic:

2x+2=6

Subtract from both sides:

(2x+2)-2=-6-2

Simplify the arithmetic:

2x=62

Simplify the arithmetic:

2x=8

Divide both sides by :

(2x)2=-82

Simplify the fraction:

x=-82

Find the greatest common factor of the numerator and denominator:

x=(-4·2)(1·2)

Factor out and cancel the greatest common factor:

x=4

11 additional steps

(3x+2)=-(x-6)

Expand the parentheses:

(3x+2)=-x+6

Add to both sides:

(3x+2)+x=(-x+6)+x

Group like terms:

(3x+x)+2=(-x+6)+x

Simplify the arithmetic:

4x+2=(-x+6)+x

Group like terms:

4x+2=(-x+x)+6

Simplify the arithmetic:

4x+2=6

Subtract from both sides:

(4x+2)-2=6-2

Simplify the arithmetic:

4x=62

Simplify the arithmetic:

4x=4

Divide both sides by :

(4x)4=44

Simplify the fraction:

x=44

Simplify the fraction:

x=1

3. List the solutions

x=4,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+2|
y=|x6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.