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Solution - Absolute value equations

Exact form: x=-1,-34
x=-1 , -\frac{3}{4}
Decimal form: x=1,0.75
x=-1 , -0.75

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+2|=|5x+4|
without the absolute value bars:

|x|=|y||3x+2|=|5x+4|
x=+y(3x+2)=(5x+4)
x=y(3x+2)=(5x+4)
+x=y(3x+2)=(5x+4)
x=y(3x+2)=(5x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+2|=|5x+4|
x=+y , +x=y(3x+2)=(5x+4)
x=y , x=y(3x+2)=(5x+4)

2. Solve the two equations for x

12 additional steps

(3x+2)=(5x+4)

Subtract from both sides:

(3x+2)-5x=(5x+4)-5x

Group like terms:

(3x-5x)+2=(5x+4)-5x

Simplify the arithmetic:

-2x+2=(5x+4)-5x

Group like terms:

-2x+2=(5x-5x)+4

Simplify the arithmetic:

2x+2=4

Subtract from both sides:

(-2x+2)-2=4-2

Simplify the arithmetic:

2x=42

Simplify the arithmetic:

2x=2

Divide both sides by :

(-2x)-2=2-2

Cancel out the negatives:

2x2=2-2

Simplify the fraction:

x=2-2

Move the negative sign from the denominator to the numerator:

x=-22

Simplify the fraction:

x=1

12 additional steps

(3x+2)=-(5x+4)

Expand the parentheses:

(3x+2)=-5x-4

Add to both sides:

(3x+2)+5x=(-5x-4)+5x

Group like terms:

(3x+5x)+2=(-5x-4)+5x

Simplify the arithmetic:

8x+2=(-5x-4)+5x

Group like terms:

8x+2=(-5x+5x)-4

Simplify the arithmetic:

8x+2=4

Subtract from both sides:

(8x+2)-2=-4-2

Simplify the arithmetic:

8x=42

Simplify the arithmetic:

8x=6

Divide both sides by :

(8x)8=-68

Simplify the fraction:

x=-68

Find the greatest common factor of the numerator and denominator:

x=(-3·2)(4·2)

Factor out and cancel the greatest common factor:

x=-34

3. List the solutions

x=-1,-34
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+2|
y=|5x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.