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Solution - Absolute value equations

Exact form: x=13
x=\frac{1}{3}
Decimal form: x=0.333
x=0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+2|=|3x4|
without the absolute value bars:

|x|=|y||3x+2|=|3x4|
x=+y(3x+2)=(3x4)
x=y(3x+2)=(3x4)
+x=y(3x+2)=(3x4)
x=y(3x+2)=(3x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+2|=|3x4|
x=+y , +x=y(3x+2)=(3x4)
x=y , x=y(3x+2)=(3x4)

2. Solve the two equations for x

5 additional steps

(3x+2)=(3x-4)

Subtract from both sides:

(3x+2)-3x=(3x-4)-3x

Group like terms:

(3x-3x)+2=(3x-4)-3x

Simplify the arithmetic:

2=(3x-4)-3x

Group like terms:

2=(3x-3x)-4

Simplify the arithmetic:

2=4

The statement is false:

2=4

The equation is false so it has no solution.

12 additional steps

(3x+2)=-(3x-4)

Expand the parentheses:

(3x+2)=-3x+4

Add to both sides:

(3x+2)+3x=(-3x+4)+3x

Group like terms:

(3x+3x)+2=(-3x+4)+3x

Simplify the arithmetic:

6x+2=(-3x+4)+3x

Group like terms:

6x+2=(-3x+3x)+4

Simplify the arithmetic:

6x+2=4

Subtract from both sides:

(6x+2)-2=4-2

Simplify the arithmetic:

6x=42

Simplify the arithmetic:

6x=2

Divide both sides by :

(6x)6=26

Simplify the fraction:

x=26

Find the greatest common factor of the numerator and denominator:

x=(1·2)(3·2)

Factor out and cancel the greatest common factor:

x=13

3. Graph

Each line represents the function of one side of the equation:
y=|3x+2|
y=|3x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.